목차

기하분포 (Geometric Distribution)

표기

받침

$$ x \in \{ \ 0 \ , \ 1 \ , \ 2 \ , \ \cdots \ \} $$

확률밀도함수

$$ p(x) = p \ (1-p)^{x} = p \ q^{x} $$

누적분포함수

$$ F(x) = 1 - (1-p)^{x+1} = 1 - q^{x+1} $$

기대값

$$E(X)=\frac{1-p}{p}$$

분산

$$Var(X)=\frac{1-p}{p^{2}}$$

왜도

$$ \gamma_{1} = \frac{2 - p}{\sqrt{1-p}} = \frac{2-p}{\sqrt{q}} $$

첨도

$$ \gamma_{2} = \frac{p^{2} - 6p + 6}{1-p} = \frac{p^{2} - 6p + 6}{q} $$

특성함수

$$ \phi \ (t) = \frac{p}{1 - (1 - p) \cdot e^{ \ i t}} = \frac{p}{1 - q \cdot e^{ \ i t}} $$

적률생성함수

$$M(t)=\frac{p}{1-(1-p) \cdot e^{t}} = \frac{p}{1-q \cdot e^{t}}$$

원적률

$$ \mu'_{1} = \frac{1-p}{p} $$

$$ \mu'_{2} = \frac{(2-p)(1-p)}{p^{2}} $$

$$ \mu'_{3} = \frac{(1-p) \left[ 6+(p-6)p \right] }{p^{3}} $$

$$ \mu'_{4} = \frac{(2-p)(1-p) \left[ 12+(p-12)p \right] }{p^{4}} $$

$$ \mu'_{k} = p \ \mathrm{Li}_{-k} (1-p) $$

중심적률

$$ \mu_{2} = \frac{1-p}{p^{2}} $$

$$ \mu_{3} = \frac{(p-1)(p-2)}{p^{3}} $$

$$ \mu_{4} = \frac{(p-1)(-p^{2} +9p -9}{p^{4}} $$

$$ \mu_{k} = p \ \Phi \left( \ 1-p \ , \ -k \ , \ \frac{p-1}{p} \ \right) $$

특성